144x+144(x+2)-x^2+2x=0

Solution for 144x+144(x+2)-x^2+2x=0 equation:

144x+144(x+2)-x^2+2x=0

We add all the numbers together, and all the variables

-1x^2+146x+144(x+2)=0

We multiply parentheses

-1x^2+146x+144x+288=0

We add all the numbers together, and all the variables

-1x^2+290x+288=0

a = -1; b = 290; c = +288;
Δ = b2-4ac
Δ = 2902-4·(-1)·288
Δ = 85252
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{85252}=\sqrt{4*21313}=\sqrt{4}*\sqrt{21313}=2\sqrt{21313}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(290)-2\sqrt{21313}}{2*-1}=\frac{-290-2\sqrt{21313}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(290)+2\sqrt{21313}}{2*-1}=\frac{-290+2\sqrt{21313}}{-2}
$